Answer:
Using diagram from your another question .
Use Pythagorean theorem
[tex]\\ \rm\longmapsto AC^2=4^2+10^2=16+100=116[/tex]
[tex]\\ \rm\longmapsto AC=10.77[/tex]
Not satisfied (Close but we can't ignore 0.03)
Let required BC be x
[tex]\\ \rm\longmapsto \dfrac{x}{10.77}=cos20[/tex]
[tex]\\ \rm\longmapsto x=0.94(10.77)=10.124ft[/tex]
Camera should be shifted 0.124ft left
