Answer:
-120/169
Step-by-step explanation:
[tex]\sin{\theta} = \pm\sqrt{1-\cos^2{\theta}}=\pm\sqrt{1-(\frac{5}{13})^2}=\pm\sqrt{1-\frac{25}{169}}=\pm\sqrt{\frac{144}{169}}=\pm\frac{12}{13}[/tex]
In Quadrant IV, sinθ < 0
so sinθ = -12/13
sin2θ = 2 sinθ cosθ = 2 (5/13) (-12/13) = -120/169
