The probability that a sample chosen at random has a proportion of registered voters who vote between 0.37 and 0.39 is 0.016.
A z-table also known as the standard normal distribution table, helps us to know the percentage of values that are below (or to the left of the Distribution) a z-score in the standard normal distribution.
We know that the mean of samples of registered voters who vote is 0.38, while the standard deviation is 0.485. Therefore, the probability that a sample is chosen at random has a proportion of registered voters who vote between 0.37 and 0.39 can be written as,
[tex]P(0.37 < X < 0.39) = P(X < 0.39)-P(X < 0.37)[/tex]
[tex]= P(z < \dfrac{0.39-0.38}{0.485})-P(z < \dfrac{0.37-0.38}{0.485})\\\\= P(z < 0.02)-P(z < -0.02)\\\\=0.5080-0.4920\\\\=0.016\\\\=1.6\%[/tex]
Hence, the probability that a sample chosen at random has a proportion of registered voters who vote between 0.37 and 0.39 is 0.016.
Learn more about Z-table:
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Answer:
B. 17%
Step-by-step explanation:
Trust, that's how you got this far anyways :D
