Respuesta :

#20

General truth

Conjugate base of H_2SO_3 is HSO_3^-

  • k_b=7.143×10^{-13}

On comparing

  • a=7
  • b=143
  • c=6.5
  • d=2

#23

We need PH

  • 0.2mol/L=0.2M

[tex]\\ \rm\rightarrowtail pH=-log[H_3O^+][/tex]

[tex]\\ \rm\rightarrowtail pH=-log0.2[/tex]

[tex]\\ \rm\rightarrowtail pH==-log 2-log10^{-1}[/tex]

[tex]\\ \rm\rightarrowtail pH=-0.3+1[/tex]

[tex]\\ \rm\rightarrowtail pH=0.7[/tex]

Highly acidic

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