Answer:
4.0389 g
Explanation:
First step is to find how many moles of C11H22O11 12.34 grams is.
12.34 g / 330.11 g/mol = 0.03738 mol
Second, multiply the number of moles by the molar mass of C11
0.03738 mol × (11 × 12.011 g/mol) = 4.0389 g of carbon
