Answer:
[tex]x=3c\sqrt{a} -b^2[/tex]
Step-by-step explanation:
[tex]\sqrt{a} =\dfrac{x+b^2}{3c}[/tex]
Multiply both sides by 3c:
[tex]\implies \sqrt{a} \cdot 3c=\dfrac{(x+b^2) \cdot 3c}{3c}[/tex]
[tex]\implies 3c\sqrt{a} =x+b^2[/tex]
Subtract [tex]b^2[/tex] from both sides:
[tex]\implies 3c\sqrt{a} -b^2=x+b^2-b^2[/tex]
[tex]\implies 3c\sqrt{a}-b^2=x[/tex]
Switch sides:
[tex]\implies x=3c\sqrt{a} -b^2[/tex]
