Hi!
Let's solve this question,
As [tex]48x^{2} [/tex]; [tex]64 {x}^{4} [/tex]; [tex]x[/tex]; [tex]36 {x}^{2} [/tex] are in proportion, so,
[tex]48 {x}^{2} = 64 {x}^{4} = x = 36 {x}^{2} [/tex]{x ≠ 0}
(Simplification attached as image)
[tex] = > \frac{12}{ {17x}^{2} } = \frac{1}{36x} [/tex]
[tex] = > 17 {x}^{2} = 12 \times 36x[/tex]
[tex] = > 17x = 432[/tex](Divided by 17 each side)
[tex] = > x = \frac{432}{17} [/tex]
Hence, value of x is [tex] \frac{432}{17} [/tex]
