Answer:
[tex]2x+3y-45=0[/tex]
Step-by-step explanation:
The slope of the line that goes through (18, 3) and (21, 1) is
[tex]\frac{1-3}{{21-18}}=\frac{-2}{3}\\[/tex]
The slope of the line that goes through (18, 3) and (x, y) is
[tex]\frac{y-3}{{x-18}}[/tex]
So
[tex]\frac{y-3}{{x-18}} = \frac{-2}{3}\\-2(x-18)=3(y-3)\\-2x+36=3y-9\\2x+3y-45=0[/tex]
