Answer:
[tex]f^{-1} = (9x + 1)^{7}[/tex]
Step-by-step explanation:
[tex]y\:=\:\frac{x^{\frac{1}{7}}-1}{9}[/tex]
replace x with y:
[tex]x=\frac{y^{\frac{1}{7}}-1}{9}[/tex]
solve for y:
[tex]9x=y^{\frac{1}{7}}-1}[/tex]
[tex]9x + 1 = y^{\frac{1}{7} }[/tex]
[tex]y = (9x + 1)^{7}[/tex]
therefore:
[tex]f^{-1} = (9x + 1)^{7}[/tex]
