Answer:
D . [tex]\frac{AC}{DE} =\frac{BC}{BE}[/tex]
Explanation:
As AC is congruent to BC, BC is congruent to BE. We can solve them find side length.
To make it easier:
[tex]\boxed{\frac{bigger .base}{smaller .base} = \frac{bigger .side }{smaller.side}}[/tex]
