Step-by-step explanation:
[tex]\lim_{x \to \infty} \frac{3-\frac{2}{x} }{4+\frac{\sqrt{2}}{x^2}}= \lim_{x \to \infty} \frac{3-0}{4+0}=\frac{3}{4}(-).[/tex]
[tex]\lim_{x \to- \infty} \frac{3-\frac{2}{x}}{4+\frac{\sqrt{2}}{x^2}}= \lim_{x \to- \infty}\frac{3-0}{4+0}=\frac{3}{4}(+).[/tex]
For more info see the attachment.
