Answer:
[tex]3x-2y+8=0[/tex]
Step-by-step explanation:
The slope of the line that goes through the points (-2, 1) and (0, 4) is
[tex]\frac{4-1}{0-(-2)} = \frac{3}{2}[/tex]
The slope of the line that goes through the points (x, y) and (0, 4) is
[tex]\frac{4-y}{0-x} = \frac{4-y}{-x}[/tex]
So [tex]\frac{3}{2}=\frac{4-y}{-x}\\-3x=2(4-y)=8-2y\\3x-2y+8=0[/tex]
