Answer:
[tex]3\ m/s^2[/tex]
Explanation:
[tex]We\ are\ given,\\Initial\ velocity\ of\ the\ bicycle(u)=0\ m/s\\Final\ velocity\ of\ the\ bicycle(v)=9\ m/s\\Time\ taken\ to\ accelerate=3/ seconds\\We\ know\ that,\\Acceleration(a)=\frac{v-u}{t}\\ Here,\\a=\frac{9-0}{3}=\frac{9}{3}=3\ m/s^2[/tex]
