Answer:
5331.2 L of Volume
Explanation:
At standard temperature and pressure (STP) one mole of ideal gas occupies 22.4 L of volume.
Hence we can write following relation,
1 mole of Gas occupies = 22.4 L of Volume
So,
238 moles of gas will occupy = X L of Volume
Solving for X,
X = 22.4 L × 238 mole / 1 mole
X = 5331.2 L of Volume
