Respuesta :

You can use the change of base formula to get

[tex]\log_2(100) = \frac{\log(100)}{\log(2)} \approx 6.643856[/tex]

and also

[tex]\log_6(20) = \frac{\log(20)}{\log(6)} \approx 1.671950[/tex]

In general, the change of base formula is

[tex]\log_b(x) = \frac{\log(x)}{\log(b)}[/tex]

Answer:

The value of Log 2 ^ 100 is about 4 times the value of Log  6 ^ 20.

Step-by-step explanation:

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