Answer:
a=0
Step-by-step explanation:
When x=2, it is at -1, so the left and right side of x=2 must approach -1, in order for it to be defined, and must be undefined at x=1 to be continuous.
We plug in 2 in the bottom equation and set it equal to -1.
[tex]( {2}^{2} + a(2) - 5 = - 1[/tex]
[tex]4 + 2a - 5 = - 1[/tex]
[tex]2a = 0[/tex]
[tex]a = 0[/tex]
So
A=0
