Answer:
7
Step-by-step explanation:
[tex]\frac{28-(3^2-2)}{4^2-13} [/tex] = [tex]\frac{28-(9-2)}{16-13} [/tex] = [tex]\frac{28- 7}{16-13} [/tex] = [tex]\frac{21}{3} [/tex] = 7
