keeping in mind that radius is half the diameter, we know this cone has a diameter of 2 inches, so it has a radius of 1 inch, kinda small really for ice-cream, but anyhow.
[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1\\ h=6 \end{cases}\implies V=\cfrac{\pi (1)^26}{3}\implies V=2\pi \implies \underset{\textit{rounded up}}{V\approx 6}[/tex]
