[tex]y=5x-7 \\
6x-5y=12 \\ \\
\hbox{substitute 5x-7 for y in the 2nd equation:} \\
6x-5(5x-7)=12 \\
6x-25x+35=12 \\
6x-25x=12-35 \\
-19x=-23 \\
x=\frac{-23}{-19} \\
x=\frac{23}{19} \\ \\
y=5x-7=5 \times \frac{23}{19}-7=\frac{115}{19}-\frac{133}{19}=-\frac{18}{19} \\ \\
(x,y)=(\frac{23}{19},-\frac{18}{19})[/tex]
