Since you mention "exponential", I suspect the equation is supposed to read
[tex]3^{2x+3} 3^{x-2} = 81[/tex]
Recall that [tex]a^ba^c = a^{b+c}[/tex], so we can simplify the left side to get
[tex]3^{(2x+3)+(x-2)} = 81[/tex]
and since 81 = 3⁴,
[tex]3^{(2x+3)+(x-2)} = 3^4 \implies (2x+3) + (x - 2) = 4[/tex]
because the bases in the expressions on either side are the same.
Solve for x :
(2x + 3) + (x - 2) = 4
3x + 1 = 4
3x = 3
x = 1
