Answer:
[tex] \sin( \alpha ) = \frac{5}{13} \\ \sin( 2 \alpha ) = 2 \times \sin( \alpha ) \times \cos( \alpha ) \\ we \: can \: find \: \cos( \alpha ) from \: the \: traingle \: so \: \\ \cos( \alpha ) = \frac{12}{13} \\ now \: \sin(2 \alpha ) = 2 \times \frac{5}{13} \times \frac{12}{13} = \frac{120}{169} [/tex]
