Answer:
[tex]x=\frac{7}{2}\pm\frac{\sqrt{29}}{2}[/tex]
Step-by-step explanation:
[tex]-x^2+7x=5[/tex]
[tex]-x^2+7x-5=0[/tex]
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
[tex]x=\frac{-7\pm\sqrt{7^2-4(-1)(-5)}}{2(-1)}[/tex]
[tex]x=\frac{-7\pm\sqrt{49-20}}{-2}[/tex]
[tex]x=\frac{-7\pm\sqrt{29}}{-2}[/tex]
[tex]x=\frac{7}{2}\pm\frac{\sqrt{29}}{2}[/tex]
