Answer:
The answer is 0 I'm pretty sure
Step-by-step explanation:
Answer:
[tex]x=-\frac{5}{4}\pm\frac{\sqrt{89}}{4}[/tex]
Step-by-step explanation:
[tex]-2x^2-5x+25=17\\-2x^2-5x+8=0\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-5)\pm\sqrt{(-5)^2-4(-2)(8)}}{2(-2)}\\x=\frac{5\pm\sqrt{25+64}}{-4}\\x=\frac{5\pm\sqrt{89}}{-4}\\x=-\frac{5}{4}\pm\frac{\sqrt{89}}{4}\\[/tex]
