Answer:
(x +3)^2 +(y -2)^2 = 16
Step-by-step explanation:
Complete the squares.
(x^2 +6x) +(y^2 -4y) -3 = 0
(x^2 +6x +9) +(y^2 -4x +4) = 16 . . . . add 9+4+3 = 16
(x +3)^2 +(y -2)^2 = 16
_____
Additional comment
The square (x +a)^2 is (x^2 +2ax + a^2). When you have (x^2 +2ax), you complete the square by adding the square of half the x-coefficient.
