prabahar0179
prabahar0179 prabahar0179
  • 20-11-2021
  • Mathematics
contestada

Simplify: [tex]-\sqrt{16x^2}[/tex] if x<0

Respuesta :

avaneeshraj avaneeshraj
  • 20-11-2021

Answer:

[tex]$-4x$[/tex]

Step-by-step explanation:

First, let us write this equation into an easier one. We have:

[tex]$-\sqrt{16x^2}=-\sqrt{4^2x^2}$[/tex]

The exponents cancel out with the square root, so we have:

[tex]-4x[/tex]

as our answer.

HOPE IT HELPS :D

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