kaihibbs kaihibbs
  • 20-11-2021
  • Mathematics
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In ΔNOP, n = 880 cm, o = 350 cm and ∠P=22°. Find ∠N, to the nearest degree.

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Аноним Аноним
  • 20-11-2021

Answer:

Step-by-step explanation:

law of cosines to find p

p² = 880² + 350² - 2(880)(350)cos22

p = 570.749... cm

law of sines to find ∠N

sin22/570.749 = sinN/880

N = 35.280 or 144.719

As n is the longest side, N must be the largest angle

∠N = 145°

or we can use law of cosines to find N

880² = 350² + 570.75² - 2(350)(570.75)cosN

N = 144.719° or 215.281°

as an angle > 180° cannot occur in a triangle.

∠N = 145°

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