Respuesta :
The equation of the circular orbit and the parabolic path of the comet are
given by the center, diameter, vertex, and directrix.
Part A: The equation of the planet's orbit is; x² + y² = 50²
Part B: The equation of the comet's orbit is; [tex]\underline{x = -\dfrac{y^2}{280} + 60}[/tex]
Part C: The planet's orbit and the comet's path do not intersect.
Reasons:
Part A: The center of the orbit = The origin (0, 0)
The diameter of the orbit = 100
Therefore;
[tex]Radius \ of \ orbit = \dfrac{100}{2} = 50[/tex]
The radius of the planet's orbit, r = 50
The equation of a circle with center (h, k) is; (x - h)² + (y - k)² = r²
Therefore, the equation of the circle is (x - 0)² + (y - 0)² = r²
Which gives;
x² + y² = 50²
Part B: The directrix of the parabolic path is x = 70
The vertex = (60, 0)
Therefore, -p = 70
[tex]The \ equation \ is \ x = \dfrac{1}{4\cdot p} \cdot (y - k)^2 + h[/tex]
Which gives;
[tex]The \ equation \ is \ x = \dfrac{1}{4\times (-70)} \times (y - 0)^2 + 60 = -\dfrac{y^2}{280} + 60[/tex]
[tex]x = \mathbf{ -\dfrac{y^2}{280} + 60}[/tex]
The equation of the comet's path in standard form is [tex]\underline{x = -\dfrac{y^2}{280} + 60}[/tex]
Part C: At the point where the path intersect, we have;
[tex]x^2 = \left( -\dfrac{y^2}{280} + 60 \right)^2[/tex]
Therefore;
[tex]\mathbf{\left( -\dfrac{y^2}{280} + 60 \right)^2} = 50^2 - y^2[/tex]
Let y² = a, we get;
[tex]\left( -\dfrac{a}{280} + 60 \right)^2 = 50^2 -a[/tex]
a ≈ -2015.693 and a ≈ -42784.31
y ≈ √(-2015.693) or y ≈ √-42784.31) (imaginary numbers)
The planet's orbit does not intersect the path of the comet.
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https://brainly.com/question/20743199
