Given, ∠3 = 126°.
∠3 =∠1 = 126° (vertically opp. angles)
∠3 =∠5 = 126° (alternate interior angles)
∠3 =∠7 = 126° (corresponding angles)
Now, ∠2 = 180° - 126° = 54° (linear pair/supplementary angles)
∠2 = ∠4 = 54° (vertically opp. angles)
∠2 = ∠8 = 54° (alternate interior angles)
∠8 = ∠6 = 54° (vertically opp. angles)
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