Answer:
[tex](\frac 32, 0)[/tex]
Step-by-step explanation:
I'm assuming that there was a | at the beginning so it's [tex]f(x) = |2x-3|[/tex]. With this kind of plots you get angular points where the graph of the "original" function - ie the one without the absolute value - would cross the x-axis. In this case, when [tex]2x-3 = 0 \rightarrow x= \frac32[/tex]
