Answer:
Explanation:
how many grams and moles of gold are present in 8.09 x 10^28 atoms of gold?
there are 6.02 x 10^23 molecules or atoms in 1 mole
of a compound or element
8.09 x 10^28 /(6.02 x 10^23) = 1.34 x 10^5 moles of Au
1 mole of gold (see periodic table for #79) 197 g
so 1.34 x 10^5 moles of Au weigh
197 x 1.34 x 10^5 = 2.64 x 10^7 g
your little gold treasure is worth
Gold Price Per Gram $59.87 x 2.64 x 10^7=
$$ 1.58 x 10^9
=$ 1,580,000,000
