Answer:
1) Convert percent (m/V) to molarity
percent (m/V)=1.15 grams/100ml=1.15 g/0.1L=11.5g/L
molarity of KBr=mol/L=g/L *(1mol/molecular weight of KBr)=(11.5g/L) * (1mol/119.0g/mol)=0.0966 mol/L=0.0966M
2) calculation of osmol from mol
In solution, KBr dissociates into two ions K+ and Br- so there are 2 osmol of KBr per mol
3) calculation of osmolarity=molarity*2=0.0966*2=0.193 Osm or Osmolar
Explanation:
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