[tex]y = -3x + 27[/tex]
Step-by-step explanation:
A parallel line will have the same slope as the given line so we can write the slope-intercept form of the equation as
[tex]y = -3x + b[/tex]
Since the other line goes through the point (9, 0), we can use this to solve for b:
[tex]0 = -3(9) + b \Rightarrow b = 27[/tex]
Therefore, the equation of the parallel line that goes through (9, 0) is
[tex]y = -3x + 27[/tex]
