Answer:
[tex]\frac{3+/-i\sqrt{55} }{2}[/tex]
Step-by-step explanation:
[tex]x^2-3x=16[/tex]
Subtract 16 from both sides;
[tex]x^2-3x-16=0[/tex]
[tex]\frac{-(-3)+/-\sqrt{(-3^2)-4(-16)} }{2}=\frac{3+/-\sqrt{9-64} }{2}=\frac{3+/-\sqrt{-55} }{2}=\frac{3+/-\sqrt{55i^2} }{2} =\frac{3+/-i\sqrt{55} }{2}[/tex]
