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  • 19-10-2021
  • Mathematics
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Factor y^2+2y−48. The factored expression is .

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Аноним Аноним
  • 19-10-2021

Answer:

Step-by-step explanation:

1) Use the sum-product pattern:

[tex]y^{2} +2y-48\\y^{2} -8y-6y-48[/tex]

2) Common factor from the two pairs:

[tex]y^{2} +8y-6y-48\\y(y+8)-6(y+8)[/tex]

3) Rewrite in factored form:

[tex]y(y+8)-6(y+8)\\(y-6)(y+8)[/tex]

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