No. of proton=3
No. of electron =3
No. of neutron=4
●Atm no. = no. of protons (always)
THEREFORE Atm no.=3
●No.of p= no. of e (Neutral atom)
hence here no. of p = no. of e =3 Therefore it is Neutral atom
●Mass No.=no. of p + no of neutron
Massno.=3+4=7
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So Atm no.=3
Mass no.=7
Therefore it is Li atom.
Net charge=0( as no. of p= no. of e)
THANK YOU.
