[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]
In the right triangle ABC,
1) tan A
3) sin A
2) tan B
4) sin B
[tex] \huge \boxed{\mathfrak{Answer} \downarrow}[/tex]
In a right ∆ ACB,
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1) tan A = Opposite side of angle A/ Adjacent side of angle A = BC/AC.
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2) sin A = Opposite side of angle A/Hypotenuse = BC/AB.
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3) tan B = Opposite side of angle B/ Adjacent side of angle B = AC/BC.
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4) sin B = Opposite side of angle B/Hypotenuse = AC/AB.
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