Answer:
8 and 9
Step-by-step explanation:
Consider perfect squares either side of 80.49 , that is
64 < 80.49 < 81 , then
[tex]\sqrt{64}[/tex] < [tex]\sqrt{80.49}[/tex] < [tex]\sqrt{81}[/tex] , so
8 < [tex]\sqrt{80.49}[/tex] < 9
