Respuesta :
Using the range rule of thumb, it is found that:
- Scores of 9.1 or lower are significantly low.
- Scores of 30.3 or higher are significantly high.
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The z-score of a measure X, in a distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
- It measures how many standard deviations X is from the mean.
- From the range rule of thumb, if Z <= -2, the measure is significantly low, and if Z >=2, it is significantly high.
- Mean of 19.7, thus [tex]\mu = 19.7[/tex].
- Standard deviation of 5.3, thus [tex]\sigma = 5.3[/tex].
Scores that are significantly low:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-2 = \frac{X - 19.7}{5.3}[/tex]
[tex]X - 19.7 = -2(5.3)[/tex]
[tex]X = 9.1[/tex]
Scores of 9.1 or lower are significantly low.
Scores that are significantly high:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]2 = \frac{X - 19.7}{5.3}[/tex]
[tex]X - 19.7 = 2(5.3)[/tex]
[tex]X = 30.3[/tex]
Scores of 30.3 or higher are significantly high.
A similar problem is given at https://brainly.com/question/24126815