[tex]\Large\underline{\rm Solution :- }[/tex]
The given inequality to us is ,
[tex]\implies ( x -3)(x +5) \leq 0 [/tex]
So that ,
[tex]\implies x \leq 3[/tex]
[tex]\implies x \leq -5[/tex]
This implies x can have a value of greater than or equal to -5 to less than or equal to 3 . Hence ,
In Set builder Notation :-
[tex]\implies \underline{\boxed{ x | -5 \leq x \leq 3 }}[/tex]
In interval notation :-
[tex]\implies \underline{\boxed{ x \in [ -5,3] }}[/tex]
