Answer
D. 2 sinx / (1-cos x)
Step-by-step explanation:
[tex]\frac{sec x*sin(-x)+tan (-x)}{1+sec(-x)} \\=\frac{\frac{1}{cos x}*(-sin x)-\frac{sin x}{cos x} }{1-\frac{1}{cos x} }\\=\frac{-sin x-sin x}{cos x -1} \\=\frac{-2sin x}{cos x -1} \\=\frac{2sin x}{1-cos x}[/tex]
