donovanhoward208
donovanhoward208 donovanhoward208
  • 17-09-2021
  • Mathematics
contestada

16. What is the equation of a line
that is perpendicular to the line
y=2x + 1 and passes through the
point (4, 6)?

Respuesta :

Heather
Heather Heather
  • 19-09-2021

Answer:

y = -[tex]\frac{1}{2}[/tex]x + 8

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes, so the equation so far is:

y = -[tex]\frac{1}{2}[/tex]x + b

To find our b (y-axis intercept) we will plug in the points given

(equation) y = -[tex]\frac{1}{2}[/tex]x + b

(plug-in) 6 = -[tex]\frac{1}{2}[/tex](4) + b

(multiply) 6 = -2 + b

(add 2 to both sides) 8 = b

(answer) b = 8

(plug-in b) y = -[tex]\frac{1}{2}[/tex]x + 8

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