d = 10in
r = 5in
AREA OF THE FIGURE:
[tex] = \frac{2\pi {r}^{3} }{3} + \pi {r}^{2} h[/tex]
[tex] = 2({5}^{2} )\pi + ({5}^{2} )(4)\pi[/tex]
[tex] = 2(25)\pi + 4(25)\pi[/tex]
[tex] = 50\pi + 100\pi[/tex]
[tex] = 150\pi[/tex]
[tex] = 150 \times 3.14[/tex]
[tex] = 471[/tex]
