Exponential Functions
Answer:
[tex] &x &y \\ &-2 &\frac{1}{36} \\ &-1 &\frac{1}{6} \\ &0 &1 \\ &1 &6 \\ &2 &36[/tex]
Step-by-step explanation:
Given:
[tex]g(x) = 6^x[/tex]
Solutions:
[tex]g(-2) = 6^{-2} \\ g(-2) = \frac{1}{6^2} \\ g(-2) = \frac{1}{36}[/tex]
[tex]g(-1) = 6^{-1} \\ g(-1) = \frac{1}{6}[/tex]
[tex]g(0) = 6^0 \\ g(0) = 1[/tex]
[tex]g(1) = 6^1 \\ g(1) = 6[/tex]
[tex]g(2) = 6^2 \\ g(2) = 36[/tex]
