Let x = first consecutive integer x + 1 = second consecutive integer x + 2 = third consecutive integer Based on the problem, we equate x + x + 1 + x + 2 = 72 Solving for x, 3x = 72 - 1 - 2 3x = 69 x = 69/3 x = 23 Thus, the three integers are 23, 24 and 25.
