Respuesta :

nobillionaireNobley
L(x) = f'(a)(x - a)
f(x) = x^(-1), f'(x) = -x^(-2)
Let a = 1, f'(a) = -(1)^(-2) = -1
L(0.9) = f'(1)(0.9 - 1) = -1(-0.1) = 0.1

Therefore, linear approximation of f(x) = x^(-1) for x = 0.9 is 0.1

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