Hello!
First, let's write the problem.
[tex]3x+\frac{1}{5}y=7[/tex]
Subtract 3x from both sides.
[tex]3x+\frac{1}{5}y-3x=7-3x[/tex]
[tex]\frac{1}{5}y=7-3x[/tex]
The opposite of division is multiplication, so we are going to multiply in order to undo the fraction.
[tex]5\cdot \frac{1}{5}y=5\cdot \:7-5\cdot \:3x[/tex]
Our final answer would be,
[tex]y=35-15x[/tex]
Thanks!
-TetraFish
