Answer:
D
Step-by-step explanation:
Multiply the numerator and denominator by the conjugate of the denominator.
Note that i² = - 1
The conjugate of 10 + 3i is 10 - 3i , then
[tex]\frac{(3+5i)(10-3i)}{(10+3i)(10-3i)}[/tex] ← Expand numerator/denominator using FOIL
= [tex]\frac{30-9i+50i-15i^2}{100-30i+30i-9i^2}[/tex] ← simplify
= [tex]\frac{30+41i+15}{100+9}[/tex]
= [tex]\frac{45+41i}{109}[/tex] → D
