Hi ;-)
[tex]-10\dfrac{2}{7}:(-4\dfrac{4}{11})=-\dfrac{10\cdot7+2}{7}:(-\dfrac{4\cdot11+4}{11})=\\\\\\=-\dfrac{70+2}{7}:(-\dfrac{44+4}{11})=-\dfrac{72}{7}:(-\dfrac{48}{11})=-\dfrac{72}{7}\cdot(-\dfrac{11}{48})=\dfrac{99}{42}=\boxed{2\frac{15}{42}}[/tex]
