Answer:
[tex]7xyz + 21 {x}^{2} y [/tex]
factorise out 7, x and y:
[tex] = 7xy(z + 3x)[/tex]
[tex]\huge\boxed{\sf 7xy (z + 3x)}[/tex]
Step-by-step explanation:
[tex]\sf 7xyz +21x^2y\\\\H.C.F. = 7xy\\\\Hence, \ Take \ 7xy \ as \ common\\\\= 7xy (z + 3x)\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
