dunn2003
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[tex] n - \sqrt{c + 5 = 1} [/tex]
in the equation above, C is a constant. If n= 5, what is the value of c?

Could you say how you got rid of the negative sign in front of the square root in the process plz

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Respuesta :

Answer:

c=11

Explanation:

[tex]n - \sqrt{c + 5} = 1[/tex]

[tex]5 - \sqrt{c + 5} = 1[/tex]

Add sqr root of c+5 to both sides

[tex]5 = 1 + \sqrt{c + 5} [/tex]

[tex]4 = \sqrt{c + 5} [/tex]

[tex]16 = c + 5[/tex]

[tex]c = 11[/tex]

Answer:

c is 11

Explanation:

[tex]n - \sqrt{c + 5 } = 1 \\ 5 - \sqrt{c + 5} = 1 \\ [/tex]

make -√c+5 the subject:

[tex] - \sqrt{c + 5} = 1 - 5 \\ - \sqrt{c + 5} = - 4[/tex]

divide through out by -1 :

[tex] \frac{ - \sqrt{c + 5} }{ - 1} = \frac{ - 4}{ - 1} \\ \\ \sqrt{c + 5} = 4[/tex]

square both sides;

[tex] {( \sqrt{c + 5} )}^{2} = {4}^{2} \\ c + 5 = 16 \\ c = 11[/tex]

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